In the below system, solve for y in the first equation.
x + 3y = 6 and 2x - y = 10

Solution:

Given:

x + 3y = 6 be equation (1)

2x - y = 10 be equation (2)

Let us use the elimination method to solve the system of linear equations

Multiply equation (1) by 2,

2x + 6y = 12 be equation (3)

Subtract equation (2) from equation (3) we get,

(2x + 6y = 12) - (2x - y = 10)

6y + y = 12 - 10

7y = 2

y = 2/7

In the below system, solve for y in the first equation.
x + 3y = 6 and 2x - y = 10

Summary:

The solution for y in the given equation x + 3y = 6 and 2x - y = 10 is 2/7.