In the figure, △ABD and △ADC are similar. If m∠ABD = 120º, then m∠ADC = ___

Solution:
△ABD and △ADC are similar as
AB/AD = AD/AC = BD/DC
30/35 = 35/AC = BD/DC
From the above AC is calculated as
AC = (35 × 35)/30
= 245/6 = 40.83
Since BD or DC is unknown their length cannot be calculated.
Since the triangles are similar the angle ∠ABD = angle ∠ADC
So if ∠ABD = 120°
Then by the properties of the similar triangles(as stated above already)
∠ADC = 120°
In the figure, △ABD and △ADC are similar. if m∠ABD = 120º, then m∠ADC = ___
Summary:
If m∠ABD = 120º, then m∠ADC = 120º as the two triangles △ABD and △ADC are similar.
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