Solve for b₂ in A = 1/2 h(b₁ + b₂), if A = 16, h = 4, and b₁ = 3.

Solution:

Given A = 1/2 h(b\(_1\) + b\(_2\))

A = 16, h = 4, and b\(_1\) = 3

Substitute the values in the given linear equation

A = 1/2 h(b\(_1\) + b\(_2\)) ⇒ 16 = 1/2(4)(3 + b\(_2\))

⇒ 16(2) = 4(3 + b\(_2\))

⇒ 32 = 4(3 + b\(_2\))

⇒ 8 = 3 + b\(_2\)

⇒ b\(_2\) = 8 - 3 = 5

b\(_2\)= 5

Solve for b₂ in A = 1/2 h(b₁ + b₂), if A = 16, h = 4, and b₁ = 3.

Summary:

By solving A = 1/2 h(b₁ + b₂), if A = 16, h = 4, and b₁ = 3, then b₂ = 5.