Solve this system algebraically. 9x + 2y = 5 and y - 2x + 3 = 0

Solution:

Given, the equations are

9x + 2y = 5 --- (1)

⇒ y - 2x + 3 = 0

The equation can be rewritten as,

y = 2x - 3 --- (2)

Now, substituting the value of y in (1),

⇒ 9x + 2(2x - 3) = 5

⇒ 9x + 4x - 6 = 5

⇒ 13x - 6 = 5

⇒ 13x = 5 + 6

⇒ 13x = 11

⇒ x = 11/13

Now put x = 11/13 in (2),

⇒ y = 2(11/13) - 3

⇒ y = 22/13 - 3

⇒ y = (22 - 39)/13

⇒ y = -17/13

Therefore, the solutions are x = 11/13 and y = -17/13.

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Solve this system algebraically. 9x + 2y = 5 and y - 2x + 3 = 0

Summary:

Solving the system of equations 9x + 2y = 5 and y - 2x + 3 = 0 algebraically the solutions are x = 11/13 and y = -17/13.