The function g(x) is defined as g(x) = 6x² + 23x - 4. When does g(x) = 0?

Solution:

Given g(x) = 6x² + 23x - 4 ;

When a root satisfies the equation, then it is equal to zero

Equate the given equation to zero, we get

g(x) = 6x² + 23x - 4 =0

We can use quadratic formula to find the roots x = -b ± √(b² - 4ac) / 2a

Here, a = 6; b = 23; c = -4

x = {-23 ± √(23² - 4(6)(-4))} / 2(6)

x = {-23 ± √(529 + 96)} / 12

x = {-23 ± √625} / 12

x = {-23 ± 25} /12

x = -48/12, 2/12

x = -4, 1/6

Hence, when x = -4 or 1/6, the given equation becomes zero.

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The function g(x) is defined as g(x) = 6x² + 23x - 4. When does g(x) = 0?

Summary:

The function g(x) is defined as g(x) = 6x² + 23x - 4, it becomes zero when x = -4 or 1/6.