The length of a rectangle is twice its width. The perimeter is 60 ft. How do you find its area?

Solution:

Let ‘l’ be the length and ‘b’ be the breadth of the rectangle.

Given the length of a rectangle is twice its width

⇒ l = 2b

Perimeter = 2(l + b) = 60 (given)

Substitute l = 2b

Perimeter = 2 [2b + b] = 60

2(3b) = 60

b = 10

l = 2b = 2 × 10 = 20

Area of a rectangle = l × b

Area = 10 × 20 = 200 sq.ft

Therefore, the area of rectangle is 200 sq.ft

The length of a rectangle is twice its width. The perimeter is 60 ft. How do you find its area?

Summary:

The area of the rectangle whose length is twice its width and the perimeter 60 ft is 200 sq.ft