The value of (1.02)2 + (0.98)2 correct to the 3 decimal place is?
Solution:
Given, (1.02)2 + (0.98)2
We have to find the value of the above expression upto 3 decimal places.
(1.02)2 = 1.0404
(0.98)2 = 0.9604
(1.02)2 + (0.98)2 = 1.0404 + 0.9604
= 2.008
By using algebraic identity,
(a + b)2 = a2 + 2ab + b2
a2 + b2 = (a + b)2 - 2ab
Here, a = 1.02 and b = 0.98
(1.02)2 + (0.98)2 = (1.02 + 0.98)2 - 2(1.02)(0.98)
= (2)2 - 1.9992
= 4 - 1.9992
= 2.0008
Therefore, the value of (1.02)2 + (0.98)2 upto 3 decimal places is 2.001
The value of (1.02)2 + (0.98)2 correct to the 3 decimal place is?
Summary:
The value of (1.02)2 + (0.98)2 correct to the 3 decimal placs is 2.001
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