Use the result from Part C to find the two solutions to the equation 2x² - 3x - 5 = 0. Enter the two solutions separated by a comma.

Solution:

The given quadratic equation is

2x² - 3x - 5 = 0

The formula of a quadratic equation ax² + bx + c = 0 is

x = [-b ± √b² - 4ac]/2a

Here a = 2, b = -3 and c = -5

Substituting the values

x = [- (-3) ± √(-3)² - 4 (2) (-5)]/ 2(2)

x = [3 ± √9 + 40]/ 4

By further calculation

x = [3 ± √49]/4

x = [3 ± 7]/4

So we get

x = (3 + 7)/ 4 = 10/4 = 5/2

x = (3 - 7)/4 = -4/4 = -1

Therefore, the solutions are x = 5/2, -1.

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Use the result from Part C to find the two solutions to the equation 2x² - 3x - 5 = 0. Enter the two solutions separated by a comma.

Summary:

Using the result from Part C the two solutions to the equation 2x² - 3x - 5 = 0 separated by a comma are x = 5/2, -1.