# Use this equation to find dy/dx: 3y cos (x) = x^{2} + y^{2 }

**Solution:**

We can make use of uv (product rule) method of differentiation to solve the given question.

Let's solve step by step to calculate dy/dx.

Given that 3y cos (x) = x^{2} + y^{2}

Differentiating both sides with respect to x, we get

3 dy/dx cos x - 3y sin x = 2x + 2y dy/dx

⇒ 3 dy/dx cos x - 2y dy/dx = 2x + 3y sin x

By taking dy/dx common, we get

⇒ dy/dx (3 cos x - 2y) = 2x + 3y sin x

⇒ dy/dx = (2x + 3y sin x) / (3cos x - 2y)

Thus, the differential of the equation 3y cos(x) = x^{2} + y^{2}, with respect to x is dy/dx = (2x + 3y sin x) / (3cos x - 2y).

## Use this equation to find dy/dx: 3y cos (x) = x^{2} + y^{2 }

**Summary:**

The differential of the equation 3y cos (x) = x^{2} + y^{2}, with respect to x is dy/dx = (3y sin x + 2x) / (3cos x - 2y).

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