What are the first three terms of the sequence a₁ = 3 and a_n = 2(a_{n - 1})²

Solution:

Given a_n = 2(a_{n - 1})² and a₁ = 3

As given the first term would be 3

When n = 2:

a₂ = 2(a_{2 - 1})²

= 2(a₁)²

= 2(3)²

= 18

This is the second term

When n=3

a₃ = 2(a_{3 - 1})² 

= 2(a₂)²

= 2(18)²

= 648

This is the third term

Therefore, the sequence is 3, 18, 648

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What are the first three terms of the sequence a₁ = 3 and a_n = 2(a_{n - 1})²

Summary:

The first three terms of the sequence a₁ = 3 and a_n = 2(a_{n - 1})² are 3, 18, 648.