What are the foci of the ellipse graph? x²/49 + y²/64 = 1

Solution:

The equation of the ellipse is given as x²/49 + y²/64 = 1 which is of the form given below:

x²/a² + y²/b² = 1

The given ellipse has its major axis on the y - axis hence we can write:

c = √(b²- a²(1))

where b is the y-intercept of the ellipse which lies on the major axis

and a is the x-intercept of the ellipse which lies on the minor axis

From equation 1 we have

c² = b² - a²

c² = 64 - 49

c² = 15

c = √15

The foci for the ellipse are (0, √15) and (0, -√15)

What are the foci of the ellipse graph? x²/49 + y²/64 = 1

Summary:

The foci of the ellipse graph? x²/49 + y²/64 = 1 are (0, √15) and (0, -√15)