# What is a quadratic function with only the two real zeros given? x = -4 and x = -1

y = x^{4} + 5x^{3} + 5x^{2} + 5x + 4

y = x^{4} - 5x^{3} - 5x^{2} - 5x - 4

y = -x^{4} + 5x^{3} + 5x^{2} + 5x + 4

y = x^{4} + 5x^{3} + 5x^{2} + 5x - 5

**Solution:**

A quadratic function is a polynomial function with one or more variables in which the highest power of the variable is two.

In the question, we have to find a quadratic function with two real zeros given

The degree of the quadratic function is 4

The functions contains two real roots where roots has their multiplicity.

**Substitute x as -4 and -1**

If f (x) value = 0 at x = -4 and -1,

then the function contains two zeros -4 and -1

Now in y = x^{4} + 5x^{3} + 5x^{2} + 5x + 4

**Substitute x = -1**

y = (-1)^{4} + 5(-1)^{3} + 5(-1)^{2} + 5(-1) + 4 = 0

**Substitute x = -4**

y = (-4)^{4} + 5(-4)^{3} + 5(-4)^{2} + 5(-4) + 4 = 0

**Therefore, a quadratic function with only the two real zeros given is y = x ^{4} + 5x^{3} + 5x^{2} + 5x + 4.**

## What is a quadratic function with only the two real zeros given? x = -4 and x = -1

**Summary:**

A quadratic function with only the two real zeros given x = -4 and x = -1 is y = x^{4} + 5x^{3} + 5x^{2} + 5x + 4.

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