What is the discriminant of quadratic equation x² + 11x + 121 = x + 96?

Solution:

Given: Quadratic equation is x² + 11x + 121 = x + 96

We have to find the discriminant of x² + 11x + 121 = x + 96

We know that the discriminant of ax² + bx + c = 0 is given by b² - 4ac.

⇒ x² + 11x + 121 = x + 96

By transposing we get,

⇒ x² + 11x - x + 121 - 96 = 0

⇒ x² + 10 x + 25 = 0

Where, a = 1 , b = 10 and c = 25

The discriminant of ax² + bx + c = 0 is b² - 4ac

= 10² - 4(1)(25)

= 100 - 100 = 0

Therefore, the discriminant of the quadratic equation is 0.

What is the discriminant of quadratic equation x² + 11x + 121 = x + 96?

Summary:

The discriminant of the quadratic equation x² + 11x + 121 = x + 96 is 0.