# What is the equation in point-slope form of the line passing through (3, 6) and (-2, 1)?

y + 6 = 1(x + 3)

y + 1 = -1(x + 2)

y - 6 = -1(x + 3)

y - 6 = 1(x - 3)

**Solution:**

Given points are (x_{1}, y_{1}) = (3, 6)

(x_{2}, y_{2}) = (-2, 1)

Slope, m = (y_{2} - y_{1})/(x_{2} - x_{1})

= (1 - 6)/(-2 - 3)

= (-5)/(-5)

m = 1

Equation of line in slope point form is (y - y_{1}) = m (x - x_{1}) .

If (x_{1}, y_{1}) = (3, 6),

Equation is (y - 6) = 1(x - 3).

Therefore, the equation in point-slope form is (y - 6) = 1(x - 3).

## What is the equation in point-slope form of the line passing through (3, 6) and (-2, 1)?

**Summary:**

The equation in point-slope form of the line passing through (3, 6) and (-2, 1) is (y - 6) = 1(x - 3).

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