**Introduction to Point-Slope Form**

A line has an infinite number of points on it.

The equation of a line is an equation that is satisfied by each and every point on the line.

A linear equation in two variables represents a line.

The standard form of the equation of a line is:

The equation of a line can be found through various methods depending on the available information.

Some of the methods are:

- Point-slope form
- Slope-intercept form
- Intercept form
- Two-point form

We will study about the point-slope form in this section.

**Definition of Point-Slope Form**

The formula of point-slope is used to find the equation of a line.

This formula is used only when we know the slope of the line and a point on the line.

**Equation of Point-Slope Formula**

The equation of a line whose slope is \(m\) and which passes through a point \((x_1, y_1\)) is found using the point-slope formula.

The equation of the point-slope formula is:

\({y-y_1=m(x-x_1)}\) |

where \((x, y)\) is a random point on the line.

**Proof of Point-Slope Formula **

Let us consider a line whose slope is \(m\).

Let us assume that \((x_1, y_1\)) is a known point on the line.

Let \((x,y)\) be any other random point on the line whose coordinates are not known.

We know that the slope of a line is calculated using the formula:

\[ \begin{aligned}\text{Slope }&= \dfrac{ \text{Difference in y-coordinates}}{ \text{Difference in x-coordinates}}\\[0.2cm]m&= \dfrac{y-y_1}{x-x_1} \end{aligned} \]

Multiplying both sides by \((x-x_1)\),

\[m(x-x_1) = y-y_1\]

This can be written as,

\[y-y_1=m(x-x_1)\]

Hence the point-slope formula is proved.

**Examples of Point-Slope Formula**

Some examples of the point-slope formula are shown here.

- The equation of a line with slope \(-1\) and a point \((1, 2\)) is found using: \[y-2=-1(x-1)\]
- The equation of a line with slope \( \dfrac{3}{2}\) and a point \( \left( \dfrac{-1}{2}, \dfrac{2}{3} \right)\) is found using: \[y- \dfrac{2}{3}= \dfrac{3}{2} \left(x- \left(- \dfrac{1}{2} \right) \right)\]
- The equation of a line with slope \(0\) and a point \((3, -2\)) is found using: \[y-(-2) =0(x-3)\]

In each of these cases, we can simplify the equation further and get it to the form \(y=mx+b\).

**Point-Slope Formula Calculator**

Here is the point-slope formula calculator.

Here, you can find the point-slope form of a line by changing the values of \(m, x_1\) and \(y_1\).

Also, you can see how the graph changes accordingly.

- The point-slope formula of a line whose slope is \(\mathbf{m}\) and that passes through a point \(\mathbf{(x_1, y_1)}\) is \( \mathbf{y-y_1=m(x-x_1)}\)
- The equation of a horizontal line passing through \(\mathbf{(a,b)}\) is of the form \(\mathbf{y=b}\)
- The equation of a vertical line passing through \(\mathbf{(a,b)}\) is of the form \(\mathbf{x=a}\)

This is an exceptional case where the point-slope formula cannot be used.

**Solved Examples**

Example 1 |

Find the equation of a line that passes through a point \((2, -3\)) and whose slope is \( \dfrac{-1}{2}\)

**Solution:**

A point on the given line is:

\[(x_1, y_1) = (2, -3)\]

The slope of the line is:

\[m=\dfrac{-1}{2}\]

The equation of the line is found using the point-slope formula:

\[ \begin{aligned}y-y_1&=m(x-x_1)\\[0.2cm]y-(-3)&=\dfrac{-1}{2}(x-2)\\[0.2cm] y+3&= \dfrac{-1}{2}x+1\\[0.2cm] \text{Subtracting 3 } & \text{from both sides},\\[0.2cm] y&=\dfrac{-1}{2}x-2 \end{aligned}\]

Thus, the equation of the required line is

\( \therefore\) \({y=\dfrac{-1}{2}x-2}\) |

Example 2 |

Find the equation of the following line.

**Solution:**

We know that the slope of a vertical line is undefined. i.e., \(m=\infty\)

Thus, the equation of the given line can't be found using the point-slope formula.

We will use the formula listed under the "important notes" section of this page which is:

The equation of vertical line passing through \((a,b)\) is of the form \(x=a\)

Let us take any point on the line:

\[(a,b)=(4,1)\]

The equation of the line using the above formula is,

\( \therefore\) \({x=4}\) |

Example 3 |

Find the equation of a horizontal line that passes through a point \((3, 2)\)

**Solution:**

**Method 1:**

We know that the slope of a horizontal line is \(m=0\)

The line passes through the point \((x_1,y_1)=(3,2)\)

The equation of the line using the point-slope form is:

\[ \begin{aligned}y-y_1&=m(x-x_1)\\[0.2cm] y-2&=0(x-3)\\[0.2cm] y-2&=0\\[0.2cm] y&=2 \end{aligned}\]

**Method 2:**

From the formulas listed under the "important notes" section of this page, we know that:

The equation of a horizontal line passing through \((a,b)\) is of the form \(y=b\)

A point on the given line is,

\[(a,b)=(3, 2)\]

Thus, the equation of the required horizontal line is:

\[y=2\]

From both the methods, the equation of the given line is:

\( \therefore\) \({y=2}\) |

Example 4 |

Find the equation of a line that passes through two points \((1, 3)\) and \((-2, 4)\) using the point-slope form and express the answer in the standard form.

**Solution:**

The given two points are:

\[ \begin{aligned} (x_1, y_1)&=(1,3)\\[0.2cm] (x_2,y_2)&=(-2, 4) \end{aligned}\]

To use the point-slope formula, we first need to find the slope of the line.

The slope of the given line is found using:

\[ \begin{aligned} m &= \dfrac{y_2-y_1}{x_2-x_1}\\[0.2cm]&= \dfrac{4-3}{-2-1}\\[0.2cm]&= \dfrac{1}{-3}\\[0.2cm]&=- \dfrac{1}{3} \end{aligned}\] The equation of the line is found using the point-slope formula. \[ \begin{aligned} y-y_1&=m(x-x_1)\\[0.2cm]y-3&=- \dfrac{1}{3}(x-1)\\[0.2cm] y-3&=- \dfrac{1}{3} x+ \dfrac{1}{3}\\[0.2cm] \text{Adding 3 }& \text{ on both sides},\\[0.2cm] y&= - \dfrac{1}{3}x+ \dfrac{10}{3} \end{aligned}\]

To express this in the standard form, first we multiply both sides by \(3\).

\[3y=-x+10\]

Adding \(x\) on both sides,

\[x+3y=10\]

Thus, the equation of the given line in the standard form is:

\( \therefore\) \({x+3y=10}\) |

- Which of the following graphs may represent the equation \(\mathbf{y+2= -2(x-1)}\)?

**Practice Questions**

**Here are a few activities for you to practice. Select/Type your answer and click the "Check Answer" button to see the result.**

**Maths Olympiad Sample Papers**

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**Frequently Asked Questions (FAQs)**

## 1. What is the point-slope formula?

The point-slope formula is a formula that is used to find the equation of a line.

This formula is used only when we know the slope of a line and a point on the line.

The equation of a line whose slope is * m* and which passes through a point \((x_1, y_1\)) is found using the point-slope formula.

The equation of the point-slope formula is:

\( \mathbf{y-y_1=m(x-x_1)}\) |

Here \((x, y)\) is a random point on the line.

## 2. Give an example of the point-slope formula.

The equation of a line with slope **-1** and a point \((1, 2\)) is found using: \[y-2=-1(x-1)\]

You can find more examples under "Examples of Point-Slope Formula" and "Solved Examples" sections of this page.

## 3. What is the point-slope formula calculator?

You can find the point-slope formula calculator under the section "Point-Slope Formula Calculator" of this page.

Here you can change the slope * m* and the coordinates of the point \((x_1, y_1)\) and see the point-slope form and the corresponding graph as well.