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# What is the equation of a circle whose center is (3, 5) and whose radius is 2 cm?

**Solution:**

A circle is a two-dimensional figure formed by a set of points that are at a constant or at a fixed distance (radius) from a fixed point (center) in the plane.

The fixed point is called the origin or center of the circle and the fixed distance of the points from the origin is called the radius.

The standard form of the equation of a circle is given by

(x - a)^{2} + (y - b)^{2} = r^{2}

Where, a and b are the coordinates of the centre

r is the radius

Given, centre = (3,5)

Radius, r = 2 cm

Substituting the values in standard form of equation we get,

(x - 3)^{2} + (y - 5)^{2} = 2^{2}

(x - 3)^{2} + (y - 5)^{2} = 4

Therefore, the equation of the circle is (x - 3)^{2} + (y - 5)^{2} = 4.

## What is the equation of a circle whose center is (3, 5) and whose radius is 2 cm?

**Summary:**

The equation of a circle with the center (3,5) and radius = 2 cm is (x - 3)^{2 }+ (y - 5)^{2} = 4.

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