What is the length of AJ if AB II JK?
8 in, 8.75 in, 10.25 in, 14 in.

Solution:

Given, AB is parallel to JK

This implies triangle HBA and triangle HKJ are similar.

So, HB/HA = HK/HJ

From the figure,

HB = 3 inches

HA = 5.25 inches

HK = 8 inches

Now, 3/5.25 = 8/HJ

On rearranging,

HJ = 8(5.25)/3

HJ = 42/3

HJ = 14 inches

AJ = HJ - HA

AJ = 14 - 5.25

AJ = 8.75 inches.

Therefore, the length of AJ is 8.75 inches.

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What is the length of AJ if AB II JK?

Summary:

The length of AJ if AB II JK is 8.75 inches.