What is the logarithmic form of the equation e^3x ≈ 3247?

Solution:

Given equation e^3x ≈ 3247

Applying log on both sides

log(e^3x) ≈ log_e(3247)

We know that log(e^a) = a

3x = 3.511

x = 3.511/3

x = 1.17

Therefore, the value of x is 1.17

What is the logarithmic form of the equation e^3x ≈ 3247?

Summary:

The logarithmic form of the equation e^3x ≈ 3247 is 3x = log_e(3247) and the value of x is 1.17