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What is the perimeter of POR with vertices P(-2, 9) Q(7, -3) and R(-2, -3) in the coordinate plane.
Solution:
Given vertices P(-2, 9) Q(7, -3) and R(-2, -3)
By given information, we can say that the structure formed is a triangle.
Perimeter is the sum of all sides of the triangle
Perimeter = PQ + QR + PR
To find sides, we use distance between points formula
PQ = √(X - x)² +(Y - y)²
PQ = √(-2 - 7)² +(3 + 9)²
PQ = √81 + 144 = √225 =15
QR = √(X - x)² +(Y - y)²
QR = √(7 + 2)² +(3 - 3)²
QR = √81 = 9
PR = √(X - x)² +(Y - y)²
PR = √(2 - 2)² +(9 + 3)²
PR = √144 = 12
Perimeter = 15 + 9 + 12 = 36
What is the perimeter of POR with vertices P(-2, 9) Q(7, -3) and R(-2, -3) in the coordinate plane.
Summary:
The perimeter of POR with vertices P(-2, 9) Q(7, -3) and R(-2, -3) in the coordinate plane is 36 units.
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