# What is the perimeter of POR with vertices P(-2, 9) Q(7, -3) and R(-2, -3) in the coordinate plane.

**Solution:**

Given vertices P(-2, 9) Q(7, -3) and R(-2, -3)

By given information, we can say that the structure formed is a triangle.

__Perimeter__ is the sum of all sides of the triangle

Perimeter = PQ + QR + PR

To find sides, we use __distance between points__ formula

PQ = √(X - x)² +(Y - y)²

PQ = √(-2 - 7)² +(3 + 9)²

PQ = √81 + 144 = √225 =15

QR = √(X - x)² +(Y - y)²

QR = √(7 + 2)² +(3 - 3)²

QR = √81 = 9

PR = √(X - x)² +(Y - y)²

PR = √(2 - 2)² +(9 + 3)²

PR = √144 = 12

Perimeter = 15 + 9 + 12 = 36

## What is the perimeter of POR with vertices P(-2, 9) Q(7, -3) and R(-2, -3) in the coordinate plane.

**Summary:**

The perimeter of POR with vertices P(-2, 9) Q(7, -3) and R(-2, -3) in the coordinate plane is 36 units.

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