What is the product? (4y - 3)(2y2 + 3y - 5)
Solution:
Given expression is
(4y - 3)(2y2 + 3y - 5)
⇒ 4y(2y2 + 3y - 5) -3(2y2 + 3y - 5)
⇒ 8y3 + 12y2 - 20y - 6y2 - 9y + 15
⇒ 8y3 + 6y2 - 29y + 15
Therefore, the product of (4y - 3)(2y2 + 3y - 5) is 8y3 + 6y2 - 29y + 15.
What is the product? (4y - 3)(2y2 + 3y - 5)
Summary:
The product of (4y - 3)(2y2 + 3y - 5) is 8y3 + 6y2 - 29y + 15.
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