What is the value of x in the equation ln (x + 6) - ln (2x - 1) = 1?
-0.21,0.74, 1.35, 1.97
Solution:
Given that:
ln (x + 6) - ln (2x - 1) = 1
Using logarithm rule:
ln a - ln b = ln (a/b)
ln((x + 6) / (2x - 1)) = 1
((x + 6) / (2x - 1)) = e1
We know that,
e1 = 2.72
((x + 6) / (2x - 1)) ≈ 2.72
Simplifying we get,
(x + 6) = 2.72 (2x - 1)
x + 6 = 2.72 (2x) - 2.72 (1)
x + 6 = 5.44x - 2.72
8.72 = 4.44x
By cross multiplication we get,
x = 8.72 / 4.44
x = 1.97
Therefore, the value of x is 1.97.
What is the value of x in the equation ln (x + 6) - ln (2x - 1) = 1?
Summary:
The value of x in the equation ln (x + 6) - ln (2x - 1) = 1 is 1.97.
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