What is the y intercept of the plane whose equation is 4x + 5y - z = 20

Solution:

Given equation of the plane 4x + 5y - 2 = 20

In case of plane, for y-intercept, x and z are zero. It is represented as (0,y,0)

⇒ 4(0) + 5y - 0 = 20

⇒ 5y = 20

⇒ y = 4

Therefore, the coordinates are (x, y, z) = (0, 4, 0)

What is the y intercept of the plane whose equation is 4x + 5y - z = 20

Summary:

The y intercept of the plane whose equation is 4x + 5y - z = 20 is (x, y, z) = (0, 4, 0).