Which is a factor of x² + 8x - 48?

Solution:

Given the expression x² + 8x - 48=0

This is quadratic equation in the form of ax² + bx + c = 0

a = 1; b = 8; c = -48

x = {-b ± √(b² - 4ac)}/2a

= {-8 ± √(8² - 4(1)(-48))}/2(1)

= {-8 ± √(64 + 192)}/2

= {-8 ± √256}/2

= (-8 ± 16)/2

= 4, -12

Which is a factor of x² + 8x - 48?

Summary:

By factoring x² + 8x - 48, we get factors as 4, -12.