# A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?

**Solution:**

In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. [Pythagoras theorem]

AB is the length of the pole = 18 m

AC is the length of the guy wire = 24 m

BC is the distance of the stake from the pole =?

In ΔABC, ∠ABC = 90°

BC^{2} = AC^{2} - AB^{2} (Pythagoras theorem)

BC^{2} = 24^{2} - 18^{2}

BC^{2} = 576 - 324

BC^{2} = 252

BC = 2 × 3√7

BC = 6√7

The distance of the stake from the pole is 6√7 m.

**Video Solution:**

## A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?

### NCERT Class 10 Maths Solutions - Chapter 6 Exercise 6.5 Question 10:

A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?

A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. The distance of the stake from the pole is 6√7 m