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# A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?

**Solution:**

We know that, in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

AB is the length of the pole = 18 m

AC is the length of the guy wire = 24 m

BC is the distance of the stake from the pole =?

In ΔABC, ∠ABC = 90°

Using Pythagoras theorem,

BC^{2} = AC^{2} - AB^{2}

BC^{2} = 24^{2} - 18^{2}

BC^{2} = 576 - 324

BC^{2} = 252

BC = 2 × 3√7

BC = 6√7

The distance of the stake from the pole is 6√7 m.

**☛ Check: **NCERT Solutions for Class 10 Maths Chapter 6

**Video Solution:**

## A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?

NCERT Class 10 Maths Solutions Chapter 6 Exercise 6.5 Question 10

**Summary:**

A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. The distance of the stake from the pole so that the wire will be taut is 6√7 m.

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