# A piggy bank contains hundred 50p coins, fifty ₹ 1 coins, twenty ₹ 2 coins and ten ₹ 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (i) will be a 50 p coin ? (ii) will not be a ₹ 5 coin?

**Solution:**

We know that,

Probability = Number of possible outcomes/Total number of favorable outcomes.

Total number of coins = 100 + 50 + 20 + 10 = 180

Number of 50 p coins = 100

Number of Re 1 coins = 50

Number of Rs 2 coins = 20

Number of Rs 5 coins = 10

(i) Probability of drawing 50 p coin = 100/180

(ii) Probability of getting a Rs 5 coin = 10/180 = 1/18

Probability of not getting a 5 rupee coin is 1 - 1/18 = 17/18 [Since, P(E) + P(not E) = 1]

**Video Solution:**

## A piggy bank contains hundred 50p coins, fifty ₹ 1 coins, twenty ₹ 2 coins and ten ₹ 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (i) will be a 50 p coin ? (ii) will not be a ₹ 5 coin?

### NCERT Solutions for Class 10 Maths - Chapter 15 Exercise 15.1 Question 10:

**Summary:**

If a piggy bank contains hundred 50p coins, fifty ₹ 1 coins, twenty ₹ 2 coins and ten ₹ 5 coins and it is equally likely that one of the coins will fall out when the bank is turned upside down, then the probability that the coin will be a 50p coin is 100/180 and the probability that the coin will not be a ₹ 5 coin is 17/18.