from a handpicked tutor in LIVE 1-to-1 classes

# Calculate the area of the designed region in Fig. 12.34 common between the two quadrants of circles of radius 8 cm each

**Solution:**

We use the formula for the area of sectors of the circle and the area of the square to solve the problem.

In a circle with radius r and the angle at the centre with degree measure θ,

Area of a sector = θ/360° × πr^{2}

Area of a quadrant = 90°/360° × πr^{2} = 1/4 πr^{2}

Area of plain or unshaded part of the square = Area of square - Area of quadrant

= side^{2} - (1/4 × πr^{2})

= (8 cm × 8 cm) - (1/4 × 22/7 × 8 cm × 8 cm)

= 64 cm^{2} - 352/7 cm^{2}

= 96/7 cm^{2}

Area of the designed region = Area of the quadrant - Area of plain or unshaded part of the square

= (1/4 × 22/7 × 8 cm × 8 cm) - 96/7 cm^{2}

= 352/7 cm^{2} - 96/7 cm^{2}

= 256/7 cm^{2}

**☛ Check: **NCERT Solutions for Class 10 Maths Chapter 12

**Video Solution:**

## Calculate the area of the designed region in Fig. 12.34 common between the two quadrants of circles of radius 8 cm each

NCERT Solutions Class 10 Maths Chapter 12 Exercise 12.3 Question 16

**Summary:**

The area of the designed region common between the two quadrants of circles of radius 8 cm each is 256/7 cm^{2}.

**☛ Related Questions:**

- In a circular table cover of radius 32 cm, a design is formed leaving an equilateral triangle ABC in the middle as shown in Fig. 12.24. Find the area of the design.
- In Fig. 12.25, ABCD is a square of side 14 cm. With centres A, B, C and D, four circles are drawn such that each circle touch externally two of the remaining three circles. Find the area of the shaded region.
- Fig. 12.26 depicts a racing track whose left and right ends are semicircular. Fig. 12.26 The distance between the two inner parallel line segments is 60 m and they are each 106 m long. If the track is 10 m wide, find :(i) the distance around the track along its inner edge(ii) the area of the track.
- In Fig. 12.27, AB and CD are two diameters of a circle (with centre O) perpendicular to each other and OD is the diameter of the smaller circle. If OA = 7 cm, find the area of the shaded region.

visual curriculum