# Construct ΔXYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

**Solution:**

We use the basic rules of construction to solve the question given. We will use scale and compass to do the construction required.

We will draw a rough sketch of ΔXYZ with the given measure for our reference. This will help us in deciding how to proceed. Then follow the steps given below.

**Steps of construction :**

- Draw a line segment YZ of length 5 cm.
- From Y, we need a point X is at a distance of 4.5 cm. So, with Y as the center, draw an arc of radius 4.5 cm. (now X will be somewhere on this arc & our job is to find where exactly X is).
- From Z, point X is at a distance of 6 cm. So, with Z as the center, draw an arc of radius 6 cm. (now X will be somewhere on this arc, we have to fix it).
- X has to be on both the arcs drawn. So, it is the point of intersection of arcs. Mark the point of intersection of arcs as X.
- Join XY and XZ.
- Thus, XYZ is the required triangle.

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 10

**Video Solution:**

## Construct ΔXYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

Class 7 Maths NCERT Solutions Chapter 10 Exercise 10.2 Question 1

**Summary:**

ΔXYZ is constructed in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

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