# Construct an equilateral triangle of side 5.5 cm

**Solution:**

We use the basic rules of construction to solve the question given. We will use scale and compass to do the construction required.

We will draw a rough sketch of ΔABC with the given measures for our reference. This will help us in deciding how to proceed. Then follow the steps given below.

Steps of construction -

- Draw a line segment BC of length 5.5 cm.
- From B, we need a point A is at a distance of 5.5cm. So, with B as center, draw an arc of radius 5.5cm (Now A will be somewhere on this arc. Our job is to find where exactly A is).
- From C, point A is also at a distance of 5.5cm. So, with C as the center, draw an arc of radius 5.5cm (Now A will be somewhere on this arc, we have to fix it).
- A has to be on both the arcs drawn. So, it is the point of intersection of arcs. Mark the point of intersection of arcs as A
- Join AB and AC.
- Thus, ABC is the required triangle.

**ā Check: **Class 7 Maths NCERT Solutions Chapter 10

**Video Solution:**

## Construct an equilateral triangle of side 5.5 cm

Class 7 Maths NCERT Solutions Chapter 10 Exercise 10.2 Question 2

**Summary:**

An equilateral triangle of side 5.5 cm is constructed.

**ā Related Questions:**

- Let L Be A Line And P Be A Point Not On L Through P Draw A Line M Parallel To L Now Join P To Any Point Q On L Choose Any Other Point R On M Through R Draw A Line Parallel To Pq
- Construct Abc Such That Ab 25 Cm Bc 6 Cm And Ac 65 Cm Measure B
- Construct Xyz In Which Xy 45 Cm Yz 5 Cm And Zx 6cm
- Draw Pqr With Pq 4 Cm Qr 35 Cm And Pr 4 Cm What Type Of Triangle Is This

Math worksheets and

visual curriculum

visual curriculum