Find equation of the line parallel to the line 3x – 4 y + 2 = 0 and passing through the point (- 2, 3)

Solution:

The given equation of a line is

3x – 4 y + 2 = 0

y = 3x/4 + 2/4

y = 3x/4 + 2/4, which is of the form y = mx + b

Therefore, slope of the given line is 3/4

It is known that parallel lines have the same slope.

Slope of the other line is m = 3/4

Now, the equation of the line that has a slope of 3/4 and passes through the points (-2, 3) is

(y - 3) = 3/4 {x - (- 2)}

4 y - 12 = 3x + 6

3x - 4 y + 18 = 0

NCERT Solutions Class 11 Maths Chapter 10 Exercise 10.3 Question 7

Find equation of the line parallel to the line 3x - 4 y + 2 = 0 and passing through the point (- 2, 3).

Summary:

The equation of the line parallel to the line 3x - 4 y + 2 = 0 and passing through the point (- 2, 3) is 3x - 4 y + 18 = 0