# Find the product:

(i) 9/2 × (-7/4) (ii) 3/10 × (- 9)

(iii) -6/5 × 9/11 (iv) 3/7 × (-2/5)

(v) 3/11 × 2/5 (vi) 3/(-5)× -5/3

**Solution:**

We will be finding the product of numerator and denominator to get the results of the given products.

(i) 9/2 × (- 7/4) = [(9 × (- 7)]/(2 × 4) = - 63/8

(ii) 3/10 × (- 9) = (3/10) × (- 9/1) = [(3 × (- 9)]/(10) = - 27/10

(iii) - 6/5 × 9/11 = (- 6 × 9)/(5 × 11)= - 54/55

(iv) 3/7 × (-2/5) = [3 × (- 2)]/(7 × 5) = - 6/35

(v) 3/11 × 2/5 = (3 × 2)/(11 × 5) = 6/55

(vi) 3/(- 5) × (- 5/ 3)= [3 × (- 5)]/(- 5 × 3)= -15/(-15) = 1

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 9

**Video Solution:**

## Find the product: (i) 9/2 × (-7/4) (ii) 3/10 × (- 9) (iii) -6/5 × 9/11 (iv) 3/7 × (-2/5) (v) 3/11 × 2/5 (vi) 3/(-5)× -5/3

Class 7 Maths NCERT Solutions Chapter 9 Exercise 9.2 Question 3

**Summary:**

The product of the following: (i) 9/2 × (-7/4) (ii) 3/10 × (- 9) (iii) -6/5 × 9/11 (iv) 3/7 × (-2/5]) (v) 3/11 × 2/5 (vi) 3/(-5) × -5/3 are as follows: (i) - 63/8 (ii) - 27/10 (iii) - 54/55 (iv) - 6/35 (v) 6/55 (vi) 1

**☛ Related Questions:**

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