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# Find the sum:

(i) 5/4 + (-11/4)

(ii) 5/3 + 3/5

(iii) -9/10 + 22/15

(iv) -3/(-11) + 5/9

(v) -8/19 + (-2)/57

(vi) -2/3 + 0

(vii) -2 ^{1}/_{3 }+ 4 ^{3}/_{5}

**Solution:**

To solve this question, we will take the L.C.M of denominator or convert the given fractions into like fractions.

(i) 5/4 + (-11/4)

= 5/4 -11/4

= (5 - 11)/4

= - 6/4

= - 3/2

(ii) 5/3 + 3/5

Taking L.C.M of 3 and 5 , we get 15

5/3 + 3/5

= (5 × 5)/(3 × 5) + (3 × 3)/(5 × 3)

= 25/15 + 9/15

= (25 + 9)/15

= 34/15

(iii) -9/10 + 22/15

Taking L.C.M of 10 and 15 , we get 30

-9/10 + 22/15

= (- 9 × 3)/30 + (22 × 2)/30

= -27/30 + 44/30

= 17/30

(iv) -3/(-11)+ 5/9

Taking L.C.M of 11 and 9 , we get 99

-3/(-11)+ 5/9

= (-3 × 9)/(-99) + (5 × 11)/99

= 27/99 + 55/99

= 82/99

(v) - 8/19 + ( -2)/57

Taking L.C.M of 19 and 57, we get 57

-8/19 + ( -2)/57

= (-8 × 3)/(19 × 3) + (-2 × 1)/(57 × 1)

= -24/57 + (-2/ 57)

= (-24 - 2)/57

= -26/57

(vi) -2/3 + 0

Taking L.C.M of 3 and 1, we get 3

-2/3 + 0

= (-2 × 1)/3 + (0 × 3)/3

= -2/3 + 0/3

= (-2 + 0)/3

= -2/3

(vii) - \(2{\Large\frac{1}{3}}\) + \(4{\Large\frac{3}{5}}\)

= -7/3 + 23/5

Taking L.C.M of 3 and 5, we get 15

= (-7 × 5)/15 + (23 × 3)/15

= -35/15 + 69/15

= (-35 + 69)/15

= 34/15

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 9

**Video Solution:**

## Find the sum: (i) 5/4 + (-11/4) (ii) 5/3 + 3/5 (iii) -9/10 + 22/15 (iv) -3/(-11) + 5/9 (v) -8/19 + (-2)/57 (vi) -2/3 + 0 (vii) -2 ^{1}/_{3 }+ 4 ^{3}/_{5}

Class 7 Maths NCERT Solutions Chapter 9 Exercise 9.2 Question 1

**Summary:**

The sum of the following (i) 5/4 + (-11/4) (ii) 5/3 + 3/5 (iii) -9/10 + 22/15 (iv) -3/(-11) + 5/9 (v) -8/19 + (-2)/57 (vi) -2/3 + 0 (vii) -2 ^{1}/_{3 }+ 4 ^{3}/_{5} are (i) -3/2 (ii) 34/15 (iii) 17/30 (iv) 82/99 (v) -26/57 (vi) -2/3 (vii) 34/15

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