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# Find the value of k where 31 k 2 is divisible by 6.

**Solution:**

Since 6 = 3 × 2

A __number__ divisible by 6 will be divisible both by 3 and 2.

31k2 ends in digit 2 hence it is divisible by 2

To be divisible by 3 the __sum__ of its digits have to be divisible by 3.

3 + 1 + k + 2 is divisible by 3

6 + k is divisible by 3

k = 0 or 3 or 6 or 9

**✦ Try This: **Find the value of k where 52k 8 is divisible by 8.

A number is divisible by 8 if the number made by the last three digits are divisible by 8.

The number formed by the last three digits 2k8.for 2k8 to be divisible by 8

k = 4, and 8

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 16

**NCERT Exemplar Class 8 Maths Chapter 13 Problem 63**

## Find the value of k where 31 k 2 is divisible by 6.

**Summary:**

The value of k where 31 k 2 is divisible by 6 is 0 or 3 or 6 or 9.

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