# Find the values of y for which the distance between the points P (2, - 3) and Q (10, y) is 10 units

**Solution:**

We know that the distance between the two points is given by the Distance Formula = √[( x_{2 - }x_{1 })^{2} + (y_{2} - y_{1})^{2}]

By Substituting the values of points P (2, - 3) and Q (10, y) in the distance formula, we get

PQ = √(2 - 10)² + (- 3 - y)² = 10

PQ = √(- 8)² + (3 + y)² = 10

Squaring on both sides, we get

64 + (y + 3)^{2} = 100

(y + 3)^{2} = 36

y + 3 = √36

y + 3 = ± 6

y + 3 = 6 or y + 3 = - 6

Therefore, y = 3 or - 9 are the possible values for y.

**Video Solution:**

## Find the values of y for which the distance between the points P (2, - 3) and Q (10, y) is 10 units

### NCERT Class 10 Maths Solutions - Chapter 7 Exercise 7.1 Question 8:

Find the values of y for which the distance between the points P (2, - 3) and Q (10, y) is 10 units

Final Answer: Values of y for which the distance between the points P (2, - 3) and Q (10, y) is 10 units are y = 3 or - 9