# I am the smallest number, having four different prime factors. Can you find me?

**Solution:**

We will use the concept of prime factorization to solve this.

Since it is the smallest number having four different prime factors, thus, it will be the product of the first 4 prime numbers: 2, 3, 5, and 7.

Hence, the required smallest number = 2 × 3 × 5 × 7 = 210

NCERT Solutions Class 6 Maths Chapter 3 Exercise 3.5 Question 12

## I am the smallest number, having four different prime factors. Can you find me?

**Summary:**

210 is the smallest number, having four different prime factors i.e., 2 × 3 × 5 × 7.

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