A day full of math games & activities. Find one near you.

A day full of math games & activities. Find one near you.

A day full of math games & activities. Find one near you.

A day full of math games & activities. Find one near you.

# I am the smallest number, having four different prime factors. Can you find me?

**Solution:**

We will use the concept of prime factorization to solve this.

Since it is the smallest number having four different prime factors, thus, it will be the product of the first 4 prime numbers: 2, 3, 5, and 7.

Hence, the required smallest number = 2 × 3 × 5 × 7 = 210

NCERT Solutions Class 6 Maths Chapter 3 Exercise 3.5 Question 12

## I am the smallest number, having four different prime factors. Can you find me?

**Summary:**

210 is the smallest number, having four different prime factors i.e., 2 × 3 × 5 × 7.

**☛ Related Questions:**

- Write The Greatest 4 Digit Number And Express It In Terms Of Its Prime Factors
- Write The Smallest 5 Digit Number And Express It In The Form Of Its Prime Factors
- Find All The Prime Factors Of 1729 And Arrange Them In Ascending Order Now State The Relations If Any Between The Two Consecutive Prime Factors
- The Product Of Three Consecutive Numbers Is Always Divisible By 6 Verify This Statement With The Help Of Some Examples

Math worksheets and

visual curriculum

visual curriculum