# The product of three consecutive numbers is always divisible by 6. Verify this statement with the help of some examples

**Solution:**

We will be using the concept of Divisibility by 6 to solve this.

Example 1:

Let's take three consecutive numbers 19, 20, and 21.

The product of 19 × 20 × 21 = 7980

Now divide 7980 by 6.

7980 6 = 1330

Therefore, the product of three consecutive numbers, 19, 20, and 21, is divisible by 6.

Example 2:

Let's take three consecutive numbers 11, 12, and 13.

The product of 11 × 12 × 13 = 1716

Now divide 1716 by 6.

1716 6 = 286

Therefore, the product of three consecutive numbers, 11, 12, and 13, is divisible by 6.

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.5 Question 7

## The product of three consecutive numbers is always divisible by 6. Verify this statement with the help of some examples

**Summary:**

The product of three consecutive numbers is always divisible by 6

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