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# In Fig. 9.4, the area of parallelogram ABCD is :

a. AB × BM

b. BC × BN

c. DC × DL

d. AD × DL

**Solution:**

We know that

Area of a parallelogram is the product of any side and its corresponding altitude

If AB is the base and DL is the height

Area of parallelogram = AB × DL

If AD is the base and BM is the height

Area of parallelogram = AD × BM

If DC is the base and DL is the height

Area of parallelogram = DC × DL

Therefore, the area of parallelogram is DC × DL.

**✦ Try This: **The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 6 cm and 4 cm is :

**NCERT Exemplar Class 9 Maths Exercise 9.1 Problem 4**

## In Fig. 9.4, the area of parallelogram ABCD is : a. AB × BM, b. BC × BN, c. DC × DL, d. AD × DL

**Summary:**

A parallelogram is a special kind of quadrilateral that is formed by parallel lines. In Fig. 9.4, the area of parallelogram ABCD is DC × DL

**☛ Related Questions:**

- In Fig. 9.5, if parallelogram ABCD and rectangle ABEF are of equal area, then : a. Perimeter of ABCD . . . .
- The mid-point of the sides of a triangle along with any of the vertices as the fourth point make a p . . . .
- Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is a. . . . .

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