# Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is

a. 1 : 2

b. 1 : 1

c. 2 : 1

d. 3 : 1

**Solution:**

Consider P1 as the area of first parallelogram and P2 as the area of second parallelogram

We know that

Area of parallelogram = b × h

P1 = b1 × h1

P2 = b2 × h2

From the question, b1 = b2

As the distance between two parallel lines is equal

h1 = h2

P1 = b × h …. (1)

P2 = b × h …. (2)

From equation (1) and (2)

P1 = P2

So we get

P1 : P2 = 1: 1

Therefore, the ratio of their areas is 1 : 1.

**✦ Try This: **The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals 16 cm and 19 cm is

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 9

**NCERT Exemplar Class 9 Maths Exercise 9.1 Problem 7**

## Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is a. 1 : 2, b. 1 : 1, c. 2 : 1, d. 3 : 1

**Summary:**

Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is 1: 1

**☛ Related Questions:**

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