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# Jiya walks 6 km due east and then 8 km due north. How far is she from her starting place

**Solution:**

Given, Jiya walks 6 km due east and then 8 km due north.

We have to find the distance of Jiya from her starting place.

Consider a triangle ABC,

Let C be the point from where Jiya started.

Distance travelled due east = CB = 6 km

Distance travelled due north = BA = 8 km

The distance of Jiya from her starting place.

We observe ABC is a right angled triangle.

By Pythagorean theorem,

AC² = CB² + BA²

AC² = 8² + 6²

AC² = 64 + 36

AC² = 100

Taking square root,

AC = 10 km

Therefore, the required distance is 10 km.

**✦ Try This: **Rani walks 9 km due west and then 9 km due south. How far is she from her starting place?

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 6

**NCERT Exemplar Class 7 Maths Chapter 6 Problem 113**

## Jiya walks 6 km due east and then 8 km due north. How far is she from her starting place

**Summary:**

Jiya walks 6 km due east and then 8 km due north. She is at a distance of 10 km from her starting place.

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