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# Multiply: (ab + c), (ab + c)

**Solution:**

Given, __multiply__ (ab + c), (ab + c)

⇒ (ab + c) × (ab + c) = (ab + c)²

Using the standard identity: (a + b)² = a² + 2ab + c²

= (ab)² + 2(ab)(c) + c²

= (ab)² + 2abc + c²

**✦ Try This: **Multiply: (pq + rs), (pq + rs)

Given, Multiply: (pq + rs), (pq + rs)

⇒(pq + rs) × (pq + rs)

=(pq)² + pqrs + pqrs + (rs)²

=(pq)² + 2pqrs+ (rs)²

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 9

**NCERT Exemplar Class 8 Maths Chapter 7 Problem 83(xvi)**

## Multiply: (ab + c), (ab + c)

**Summary:**

Multiplying (ab + c), (ab + c) we get, (ab)² + 2abc + c²

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