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# Multiply: (3/2)p² + (2/3)q² , (2p² - 3q²)

**Solution:**

Given, __multiply__ (3/2)p² + 2/3q² , (2p² -3q²)

⇒ [(3/2)p² + 2/3q²] × (2p² -3q²)

= 3p⁴ - (9/2)p²q² + 4/3p²q² - 2q²

**✦ Try This: **Multiply: (5/4)a² + (2/3)b² , (4a² -3b²)

Given, Multiply: (5/4)a² + (2/3)b² , (4a² -3b²)

⇒ [(5/4)a² + (2/3)b²] × [(4a² -3b²)]

=5a⁴ - (15/4)a²b² + (8/3)a²b² - 2b⁴

=5a⁴ - (13/12)a²b² - 2b⁴

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 9

**NCERT Exemplar Class 8 Maths Chapter 7 Problem 83(xix)**

## Multiply: (3/2)p² + (2/3)q² , (2p² - 3q²)

**Summary:**

Multiplying (3/2)p² + 2/3q² , (2p² -3q²), We get 3p⁴ - (9/2)p²q² + 4/3p²q² - 2q²

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