# (√10 - √5)/2. Rationalise the denominator and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236, upto three places of decimal

**Solution:**

Given, the expression is (√10 - √5)/2

We have to rationalise the denominator and evaluate the given expression.

√10 = √5 × √2

So, (√10 - √5) = (√5 × √2) - √5

Taking out common term,

= √5(√2 - 1)

Given, √5 = 2.236

√2 = 1.414

So, √5(√2 - 1) = 2.236(1.414 - 1)

= 2.236(0.414)

= 0.9257

Now, (√10 - √5)/2 = 0.9257/2

= 0.4628

Therefore, (√10 - √5)/2 = 0.463

**✦ Try This: **Rationalise the denominator of the following and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236, upto three places of decimal √12/2

Given, the expression is √12/2

We have to rationalise the denominator and evaluate the given expression.

√12 = √4 × √3 = 2√3

So, √12/2 = 2√3/2

= √3

Given, √3 = 1.732

Therefore, √12/2 = 1.732

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 1

**NCERT Exemplar Class 9 Maths Exercise 1.3 Problem 13(iii)**

## (√10 - √5)/2. Rationalise the denominator and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236, upto three places of decimal

**Summary:**

On rationalising the denominator and evaluating the expression (√10 - √5)/2 by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236, we get 0.463

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