# The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

**Solution:**

From the diagram, the area for quadrilateral will be the sum of the area of two triangles.

Area of quadrilateral ABCD = Area of ΔABC + Area of ΔADC

= 1/2 × (AC × BE) + 1/2 × (AC × FD)

= 1/2 × AC (BE + FD)

= 1/2 × 24 m (13 m + 8 m)

= 1/2 × 24 m × 21 m

= 252 m²

**☛ Check: **NCERT Solutions for Class 8 Maths Chapter 11

**Video Solution:**

## The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

Class 8 Maths NCERT Solutions Chapter 11 Exercise 11.2 Question 4

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. The area of the field is 252 m².

**☛ Related Questions:**

- The diagonals of a rhombus are 7.5 cm and 12 cm. Find its area.
- Find the area of a rhombus whose side is 5 cm and whose altitude is 4.8 cm. If one of its diagonals is 8 cm long, find the length of the other diagonal.
- The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m² is ₹ 4.
- Mohan wants to buy a trapezium shaped field. Its side along the river is parallel to and twice the side along the road. If the area of this field is 10500 m2 and the perpendicular distance between the two parallel sides is 100 m, find the length of the side along the river.

Math worksheets and

visual curriculum

visual curriculum