# The diagonal of a rectangular field is 60 meters more than the shorter side. If the longer side is 30 meters more than the shorter side, find the sides of the field

**Solution:**

Let the shorter side be x meter. Then the length of the diagonal of the field will be x+60 and the length of the longer side will be x+30.

Using the Pythagoras theorem, the value of x can be found.

By applying Pythagoras theorem:

Hypotenuse² = Side 1^{2} + Side 2^{2}

(60 + x)^{2} = x^{2} + (30 + x)^{2}

60 + 2(60)x + x^{2} = x^{2} + 30^{2} + 2(30)x + x^{2}

3600 +120x + x^{2} = x^{2} + 900 + 60x + x^{2}

3600 +120x + x^{2} - x^{2} - 900 - 60x - x^{2} = 0

2700 + 60x - x^{2} = 0

Therefore, (a + b)^{2} = a^{2} + 2ab + b^{2}

Multiplying both sides by -1:

x^{2} - 60x - 2700 = 0

Solving by quadratic formula:

Comparing with ax^{2} + bx + c = 0

a = 1, b= - 60, c = - 2700

b^{2} - 4ac = (-60)^{2} - 4(1)(-2700)

= 3600 + 10800

b^{2} - 4ac = 14400 > 0

∴ Roots exist.

x = (-b ± √ (b^{2} - 4ac)) / 2a

= (-(- 60) ± √(14400)) / 2

= [(60) ± 120] / 2

x = (60 + 120) / 2 and x = (60 - 120) / 2

x = 180 / 2 and x = - 60 / 2

x = 90 and a = - 30

Length can’t be a negative value.

Hence, x = 90

Length of shorter side is x = 90 m

Length of longer side = 30 + x = 30 + 90 = 120 m

**Video Solution:**

## The diagonal of a rectangular field is 60 meters more than the shorter side. If the longer side is 30 meters more than the shorter side, find the sides of the field

### Class 10 Maths NCERT Solutions - Chapter 4 Exercise 4.3 Question 6:

The diagonal of a rectangular field is 60 meters more than the shorter side. If the longer side is 30 meters more than the shorter side, find the sides of the field

The sides of fields are such as length of shorter side x = 90 m and length of longer side = 30 + x = 30 + 90 = 120 m if the diagonal of a rectangular field is 60 meters more than the shorter side. If the longer side is 30 meters more than the shorter side