# The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.

**Solution:**

We use the formula for the area of the circle to find the area swept by the minute hand.

We know that the minute hand completes one rotation in 1 hour or 60 minutes.

Therefore, area swept by the minute hand in 60 minutes = Area of the circle with radius equal to the length of the minute hand = πr^{2}

Using unitary method, we get

Area swept by minute hand in 1 minute = πr^{2}/60

Thus, area swept by minute hand in 5 minutes = (πr^{2}/60) × 5 = πr^{2}/12

Length of the minute hand (r) = 14 cm

It is known that the minute hand completes one rotation in 1 hour or 60 minutes

Therefore, the area swept by the minute hand in 60 minutes = πr^{2}

Therefore, the area swept by the minute hand in 5 minutes = 5/60 × πr^{2} ⇒ 1/12 πr^{2}

= 1/12 × 22/7 × 14 × 14 cm^{2}

= 154/3 cm^{2}

**Video Solution:**

## The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.

### NCERT Solutions Class 10 Maths - Chapter 12 Exercise 12.2 Question 3:

**Summary:**

The area swept in 5 minutes by the minute hand of length 14 cm of a clock is 154/3 cm^{2}.