Chord AC intersects chord BD at point P in circle Z. AP = 12m, DP = 5m, PC = 6m. What is BP?

Solution:

Chord AC intersects chord BD at point P in circle Z.

Given: AP = 12m, DP = 5m, PC = 6m

As per the given figure,

AP × CP = BP × DP

In the given circle, values of AP, CP and DP are 12m, 6m and 5m respectively .

Substituting the values in the formula, we will get,

12 × 6 = 5BP

By dividing both side by 5 we get,

BP = 72/5

BP = 14.4m

Therefore, BP is 14.4m

Chord AC intersects chord BD at point P in circle Z. AP = 12m, DP = 5m, PC = 6m What is BP?

Summary:

Chord AC intersects chord BD at point P in circle Z. AP = 12m, DP = 5m, PC = 6m, BP is 14.4m