Solve for d: d - 10 - 2d + 7 = 8 + d - 10 - 3d

Solution:

A linear equation in one variable is of the form of ax + b = 0, 

where a and b are any two integers and 

x is an unknown variable having only one solution.

It is given that

d - 10 - 2d + 7 = 8 + d - 10 - 3d

By rearranging the common terms on LHS and constants on RHS

d - 2d - d + 3d = 8 - 10 + 10 - 7

By further calculation we get

-2d + 3d = 8 - 7

d = 1

Therefore, the value of d is 1.

Solve for d: d - 10 - 2d + 7 = 8 + d - 10 - 3d

Summary:

Solving for d in d - 10 - 2d + 7 = 8 + d - 10 - 3d we get 1.