Find sin θ if cot θ = -4 and cos θ < 0.
Solution:
Given, cot θ = -4 and cos θ < 0
Clearly cot θ and cos θ both are negative.
⇒ θ is an angle from II quadrant
From OA2 = OB2 + AB2
OA2 = (-4)2 + 12
OA2 = 17 ⇒ OA = √17
cot θ = Adjacent side / Opposite = -4/1
sin θ = Opposite / Hypotenuse = 1/√17
Find sin θ if cot θ = -4 and cos θ < 0.
Summary:
If cot θ = - 2 and cos θ < 0, sin θ = 1 / √17.
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