Graph the first six terms of a sequence where a₁ = 4 and r = 2.

Solution:

The formula for geometric sequence is

a_n = a₁ × r^{n - 1}

Where r is the geometric factor

n is the integer

It is given that

a₁ = 4

Common ratio r = 2

Substituting the values

a_n = 4 × 2^{n - 1}

a₁ = 4(2)^{1 - 1} = 4

a₂ = 4(2)^{2 - 1} = 8

a₃ = 4(2)^{3 - 1} = 16

a₄ = 4(2)^{4 - 1} = 32

a₅ = 4(2)^{5 - 1} = 64

a₆ = 4(2)^{6 - 1} = 128

Therefore, the graph of the first six terms is mentioned above.

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Graph the first six terms of a sequence where a₁ = 4 and r = 2.

Summary:

The graph of the first six terms of a sequence where a₁ = 4 and r = 2 is mentioned above.