How do you write an equation of a line that passes through points (-1, 3), (2, -3)?
The general equation of a straight line can be written as y = mx + c where m is the slope and c is the y-intercept.
Answer: The equation of a line passing through the points (-1, 3) and (2, -3) is 2x +y = + 1.
Let us proceed step by step to write an equation of a line.
Let us consider the given points (-1,3) and (2,-3).
As we know that the equation of a line passing through the points (x1, y1) and (x2 , y2) is given by y - y1 = m (x - x1).
You can find the slope using Cuemath's Slope Calculator.
Hence on substituting the given points in the equation of a line, we get
y - 1 = m ( x - (-1) ) -------(1)
m = (y2 - y1) / (x2 - x1)
m = (-3 - 3) / (2 - (-1))
m = -6 / 3 = -2
Substituting value of m in equation (1), we get
y - 3 = -2 ( x + 1)
y - 3 = -2x - 2
y = -2x + 1
2x + y = 1