Identify the 33^rd term of the arithmetic sequence 9, 7 ½, 6 …

Solution:

Given sequence 9, 7 ½, 6...

This resembles the arithmetic progression where

a = 9,

d = 7 ½ - 9 = -1 ½

Arithmetic progression is defined as the sequence of numbers that differs by a constant number from the preceding term

The n^th term of the progression is given by t₃₃ = a + (n - 1)d

t₃₃ = 9 + 32(-1 ½)

t₃₃ = 9 - 48 = -39

Therefore, the 33^rd term is -39.

Identify the 33^rd term of the arithmetic sequence 9, 7 ½, 6 …

Summary:

The 33^rd term of the arithmetic sequence 9, 7 ½, 6 …is -39.